gravitation questions and answers

Question 7. Then force acting on m3 due to m1, is equal and opposite to the force acting on m3 due to m2. Question 2. According to Newton’s third law of motion, action and reaction are equal and opposite. Find the percentage change in the weight of a body when it is taken from the equator to the poles. Acceleration, g = – 9.8 m/s2 Answer: \(\frac{\iota_{1}}{t_{2}}=\sqrt{\frac{h_{1}}{h_{2}}}\) Free Question Bank for NEET Physics Gravitation. or F = G × \(\frac{m_{1} m_{2}}{r^{2}}\) ……..(3) Professionals, Teachers, Students and Kids Trivia Quizzes to test your knowledge on the subject. It is the measure of inertia of the body. Ask your doubt of gravitation and get answer from subject experts and students on TopperLearning. Acceleration, a = g = 9.8 m/s2 Here, initial velocity, u = 0 The astronaut and the spaceship are orbiting with same acceleration hence, the body does not exert any force on the sides of the spaceship. If it does, why does the earth not move towards the apple? = M + \(\frac{10}{100}\)M = M + \(\frac{M}{10}\) = \(\frac{11M}{10}\) = 1.1 M If the earth attracts two objects with equal force, can we say that their masses must be equal? Question 1. Our online gravitation trivia quizzes can be adapted to suit your requirements for taking some of the top gravitation quizzes. A: 1 kg B: 9.8 kg C: 9.8 Kg-m/Sec 2 D: 9.8 N. Answer. ∴ New weight becomes 4 times. Gravitation is the force of attraction that tends to draw together any two objects in the universe. Suppose that the radius of the earth becomes twice of its original radius without any change in its mass. At the equator. The force (F) of gravitational attraction on a body of mass m due to earth of mass M and radius R is given by Gravitation Multiple Choice Questions & Answers for competitive exams. State the universal law of gravitation. or, v = \(\sqrt{800}\) Question 3. Suppose gravity of earth suddenly becomes zero, then which direction will the moon begin to move if no other celestial body affects it? The mass of the Sun is 2 x 10 30 kg and that of the Earth is 6 x 10 24 kg. Therefore, the packets fall slowly at equator in comparison to the poles. Find out the ratio of time they would take in reaching the ground. Why? Thus a big stone will fall with the same acceleration as a small stone. Isaac Newton. u = 0 ms-1, h = 49 m, Question 15. Acceleration in downward direction = g Yes. Question 5. State the universal law of gravitation. The ‘G’ is a universal constant, i.e., its value is the same (i.e. So, both the stones will reach the ground at the same time when dropped simultaneously. At what place on the earth’s surface is the weight of a body maximum? ⇒ t = \(\sqrt{10}\) = 3.16 s We = \(\frac{G M_{e} m}{R_{e}^{2}}\) …(2) Q1. Page No: 134. These questions are quite useful to prepare the objective type questions for … These Gravitation Objective Questions with Answers are important for competitive exams like JEE, NEET, AIIMS, JIPMER etc. Question 1. Answer: In a hypothetical case, if the diameter of the earth becomes half of its present value and its mass becomes four times of its present value, then how would the weight of any object on the surface of the earth be affected? Combining (1) and (2), we get h2 = \(\frac{1}{2} g t_{2}^{2}\), Calculate the height of the building. MCQ quiz on Gravitation multiple choice questions and answers on gravitation MCQ questions quiz on gravitation objectives questions with answer test pdf. It’s what keeps us safe on the ground, as opposed to floating up through the air. Answer: It is different at different places on the surface of the earth. Question 5. For example, given the weight of, and distance between, two objects, you can calculate how large the force of gravity is between them. v2 = 2gs = 2 × 9.8 × 100 = 1960 A: Yes B: No. Question 11. Answer: This will clear students doubts about any question and improve application skills while preparing for board exams. v = \(\sqrt{1960}\)m/s = 44.2 m/s. Does the apple also attract the earth? Question 5. Answer According to question, M S = Mass of the Sun = 2×10 30 kg M E = Mass of the Earth = 6×10 24 kg R = Average distance between the Earth and the Sun = 1.5×10 11 m From Universal law of gravitation, The gravitational force is responsible for providing the necessary centripetal force which allows the earth to move around the sun at the defined path or orbit. [NCERT Exemplar] Using physics, you can calculate the gravitational force that is exerted on one object by another object. Give reasons. This test will determine your knowledge of the subject. Is the time taken by a body to rise to the highest point equal to the time taken to fall from the same height? Velocity-time graph for the ball’s motion is shown in figure. So, when dropped from the same height a body reaches the ground quicker at the poles than at the equator. As we know s = ut + \(\frac{1}{2}\) gt2 Let P and Q be the two bodies, What is the source of centripetal force that a planet requires to revolve around the sun? Gravitation Class 11 MCQs Questions with Answers. Initial speed, u = 0.5 m/s 1. 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Answer: Practice questions The gravitational force between […] Browse from thousands of Gravitation questions and answers (Q&A). Q.18 What is the weight of a body of mass 1 kg? Question 4. Why does formation of tides takes place in sea or ocean? (Where Ve is the volume of the earth) Answer: ⇒ t2 = \(\frac{98}{9.8}\) = 10 It occurs only when a body is in a state of free fall under the effect of gravity alone. Its SI unit is the same as the SI unit of force, i.e., Newton (N). Then what will happen to your weight? A: mass of the object × gravitational acceleration B: Zero ∴ 49 = 0 × t + \(\frac{1}{2}\) × 9.8 × t2 We know that F = \(\frac{G M m}{r^{2}}\) as weight of a body is the force with which a body is attracted towards the earth, Previous: Contents: Next: The earth is acted upon by gravitation of sun, even though it does not fall into the sun. It is applied to all the body present in universe It is constant of proportionality in Newton’s universal law of gravitation. Explain why all of them do not fall into the earth just like an apple falling from a tree. At the poles. 6.7 × 10-11 Nm2 kg-2) everywhere in the universe. How is gravitation different from gravity? Given m1 = 3 kg; m2 = 12 kg Answer: This law states that every body in the universe attracts every other body with a force which is directly proportional to the product of their masses and inversely proportional to square of distance between them. Answer: Given, Mass of the Sun, M = 2 x 10 30 kg Define acceleration due to gravity. Answer: Answer: Question 10. The constant ‘G’ is universal because it is independent of the nature and sizes of bodies, the space where they are kept and at the time at which the force is considered. From (1) and (2), we get t1 = t2 ⇒ Time of ascent = Time of descent. The ratio of their accelerations due to gravity at the surface is (R 1 /R 2) 2 (R 2 /R 1) 2 ... Click the "Score and Show Answer(s)" button for explanations. (ii) How long will it take to reach that height? Similarly, the force of attraction between the earth and the body Q is given by Let the mass, m3 = 0.5 kg be placed at a distance of ‘x’ m from m1, as shown in figure. Answer: Access Answers to NCERT Class 9 Science Chapter 10 – Gravitation ( All In text and Exercise Questions Solved) Exercise-10.1 Page: 134. Answer: The weight will become 16 times. Question 1. (g) At which point does the bal 1 have the same speed as when it was thrown? That is, for the second stone, t = (3.16 – 1)s = 2.16s They both hit the ground at the same time. The accepted value of G is 6.67x 1CT-11 Nm 2 kg-2. For both the stones (ii) Weight = \(\frac{G M m}{r^{2}}\), where r is the radius of the earth. Draw areal velocity versus time graph for mars. or D = \(\frac{g R^{2}}{G \frac{4}{3} \pi R^{3}}=\frac{3 g}{4 \pi G R}\), Question 6. TopperLearning’s Experts and Students has answered all of Gravitation of MAHARASHTRA Class 10 Physics questions in detail. Question 16. Therefore, the body appears to be floating weightlessly. The entire NCERT textbook questions have been solved by best teachers for you. The mass of the Earth M is 5.98 x 1024 kg and the radius of the Earth R is 6.38 x 106 m. (3 marks) This hypothesis is not correct. A comprehensive database of gravitation quizzes online, test your knowledge with gravitation quiz questions. New mass, M’=M + 10% of M The solved question papers from chapter 08 Gravitation have all type of questions may be asked in annual exams such as VSA very short answer type questions, SA short answer type questions, LA long answer type questions, VBA value based questions and HOTS higher order thinking skill based questions. If a body of mass m is placed on the surface of moon, then weight of the body on the moon is Answer: Answer: One second later, he throws another stone. What would happen to your weight? A student thought that two bricks tied together would fall faster than a single one under the action of gravity. Numericals It will remain the same on the moon, i.e., 9.8 kg. Very Short Answer Type Questions. Gravitational force between moon and the earth keeps moon in uniform circular motion around the earth. (c) At which point is the bal 1 at its maximum height? (a) No Answer: If you are a student of class 9 who is using NCERT Textbook to study Science, then you must come across Chapter 10 Gravitation. When hypothetically M becomes 4 M and R becomes \(\frac{R}{2}\). Two objects of masses ml and m2 having the same size are dropped simultaneously from heights h1 and h2, respectively. Answer: According to Newton’s third law of … How does the force of attraction between the two bodies depend upon their masses and distance between them? Question 18. CLASS 11 PHYSICS CHAPTER 8 GRAVITATION QUESTION ANSWERS, A star 2.5 times the mass of the sun and collapsed to a size of 12 km rotates with a Comment. The weight of the body on the moon is about one-sixth of its weight on the earth. Question 2. Answer: (d) The quantity G is universal constant of nature. [NCERT Exemplar] Here are some practice questions that you can try. Both C and D; [(Kg-m/Sec 2) = N] Q.19 Weight of free fall object is. On the earth, a stone is thrown from a height in a direction parallel to the earth’s surface while another stone is simultaneously dropped from the same height. Question 4. or – 0.25 = -19.6 h The universal law of gravitation was able to explain successfully. (b) At which point is the bal 1 stationary? t1 = \(\frac{u}{g}\) …(1) Question 3. Identical packets are dropped from two aeroplanes—one above the equator and other above the north pole, both at height h. Assuming all conditions to be identical, will those packets take same time to reach the surface of earth? Question 1. Answer: Answer: Answer: i.e., First stone would take 3.16 s to reach the ground. Question 9. \(\frac{W_{m}}{W_{e}}=\frac{M_{m}}{M_{e}} \times \frac{R_{e}^{2}}{R_{m}^{2}}\) …. = 0 – (0.5)2 = 2 × (-9.8) × h The earth attracts an apple. What will happen to the gravitational force between two bodies if the masses of one body is doubled? This is because acceleration due to gravity is independent of the mass of the falling body. Answer: the mass of body P = m1 Two bodies of masses 3 kg and 12 kg are placed at a distance 12 m. A third body of mass 0.5 kg is to be placed at such a point that the force acting on this body is zero. The acceleration due to gravity does not depend upon the mass of the stone or body. [NCERT Exemplar] Take g = 9.8 m/s2. F = \(G \frac{m M}{R^{2}}\) …..(1) Gravitational constant is numerically equal to the force of attraction between two masses of 1 kg that are separated by a distance of 1 m. So, the earth does not fall into the sun. The radius of the earth is 6400 km and g = 10 m/s². Answer: Here, g = 1.67 ms-2, R = 1.74 × 106 m and G = 6.67 × 10-2 Nm2 kg-2, Question 2. Take the Quiz and improve your overall Physics. Does the apple also attract the earth? Zero. [NCERT Exemplar] But the acceleration due to gravity is represented by the symbol g. Therefore, we can write 0 = u – gt1 [NCERT Exemplar] Answer: A force of 20 N acts upon a body whose weight is 9.8 N. What is the mass of the body and how much is its acceleration? The two bricks like a single body, fall with the same speed to reach the ground at the same time in case of free fall. Who formulated the universal law of gravitation? Give one example each of central force and non-central force. (a) Downward Question 19. The Following Section consists of Gravitation Questions on Physics. Question 3. If it does, why does the earth not move towards the apple? Question 9. 0 = 0.5 – 9.8t [NCERT Exemplar] If the radius of the moon is 1.74 × 106 m, calculate the mass of the moon. and radius of the moon, Rm = 1740 km What will be its speed when it has fallen 100 m? Answer. (f) Acceleration = 10 ms-2 (e) What is the ball’s acceleration at point A? Zero. Weight of the same body on the earth’s surface will be Mass is the quantity of matter contained in the body. If the mass of one body is doubled, force is also doubled. So, v2 = u2 + 2gs, (ii) As v = u2 + 2 gs When r changes to 2r, the new weight is given by The tides in the sea formed by the rising and falling of water level in the sea are due to the gravitational force of attraction which the sun and the moon exert on the water surface in the sea. Acceleration due to gravity is the acceleration acquired by a body due to the earth’s gravitational pull on it. Gravitation is the force of attraction between any two bodies while gravity refers to attraction between any body and the earth. On the moon’s surface, the acceleration due to gravity is 1.67 ms-2. Question 4. (c) At point B (3) Answer: Prove that if the earth attracts two bodies placed at same distance from the centre of the earth with the same force, then their masses are equal. Assume that g = 10 m/s2 and that there is no air resistance. Find out the speed with which he threw the second stone. The acceleration produced in the motion of a body falling under the force of gravity is called acceleration due to gravity. Give three differences between acceleration due to gravity (g) and universal gravitational constant (G). Question 12. t2 = u/g …(2) Original weight, W0 = mg = mG \(\frac{M}{R^{2}}\) ∴ W = \(\frac{G M m}{r^{2}}\) What does a small value of G indicate? g = 9.8 ms-2, h = 49 m, t = 2.16 s, u = ? Answer: Which stone would reach the ground first and why? F ∝ \(\frac{m_{1} \times m_{2}}{r^{2}}\) Now, mass of the earth, Me = 6 × 1024 kg Derive an expression for acceleration due to gravity in terms of mass of the earth (M) and universal gravitational constant (G). Answer: Question 5. (f) What is the bal l’s acceleration at point B? Calculate the value of acceleration due to gravity g using the relation between g and G. But we know, acceleration ∝ 1/m. Suppose the mass of the moon is Mm and its radius is Rm. And the mass of body Q=m2 Since, the two forces, i.e., Fp and FQ are equal, thus from (1) and (2), For the first stone Q.17 Does the gravitational force same for two objects inside and outside the water? Answer: We know from Newton’s second law of motion that the force is the product of mass and acceleration. Why? Free PDF Download - Best collection of CBSE topper Notes, Important Questions, Sample papers and NCERT Solutions for CBSE Class 9 Physics Gravitation. mg = \(G \frac{m M}{R^{2}}\) or g = \(\frac{G M}{R^{2}}\) …(3) Answer: Question 21. (i) How high will it go before it begins to fall? Answer: (d) Acceleration = 10 ms-2 The way the world works is exciting. Why can one jump higher on the surface of the moon than on the earth? (2) (d) What is the ball’s acceleration at point C? F ∝ m1 × m2…(1) Free Question Bank for 11th Class Physics Gravitation Gravitation Conceptual Problems As per the universal law of gravitation, the force of attraction between the earth and the body P is given by, 3. We know that g = \(\frac{G M}{R^{2}}\) or M = \(\frac{g R^{2}}{G}\) If the mass of a body is 9.8 kg on the earth, what would be its mass on the moon? Answer: (i) Original weight = \(\frac{G M m}{r^{2}}\), where M is the mass of the earth. Find the position of that point. When a body is dropped from a height, what is its initial velocity? Answer: Justify your answer. ans F ∝ \(\frac{1}{r^{2}}\) ..(2) OTP has been sent to your mobile number and is valid for one hour Why is ‘G’ called the universal gravitational constant? Register online for Science tuition on Vedantu.com to score more marks in your examination. When M changes to new mass M’ Answer: ∴ For the second stone, Question 2. Then weight becomes Wn = mG \(\frac{4 M}{\left(\frac{R}{2}\right)^{2}}\) = (16 m G) \(\frac{M}{R^{2}}\) = 16 × W0 Derive expression for force of attraction between two bodies and then define gravitational constant. Asked by Umesh 1st December 2017 9:49 AM . Gravitation Class 9 Extra Questions Short Answer Questions-I. Question 20. If the radius of the earth becomes twice of its original radius, then part1, Page 1 ⇒ Average density of the earth, D = \(\frac{\text { Mass }}{\text { Volume }}=\frac{g R^{2}}{G \times V e}\) Where, R is the distance of the body from the centre of the earth. As the body falls back to the earth with the same velocity it was thrown vertically upwards. Yes. Question 3. Because the value of acceleration due to gravity (g) on the moon’s surface is nearly l/6th to that of the surface of the earth. Answer: Answer: Prove that if a body is thrown vertically upward, the time of ascent is equal to the time of descent. Will this ratio remain the same if (i) one of the objects is hollow and the other one is solid; and (ii) both of them are hollow, size remaining the same in each case? The standard kilogram is the mass of a block of a platinum alloy kept at the international bureau of weights and measures near Paris in France. Why does a body orbiting in space possess zero weight with respect to a spaceship? Observe the graph and answer the following questions. Calculate its speed after 2 s. Also find the speed with which the stone strikes the ground. v = u + gt2 3. So, acceleration = \(\frac{\text { Force }}{\text { Mass }}=\frac{20}{1}\) = 20 m/s2, Question 3. where G is a constant known as universal gravitational constant. We know that G = 6.67 × 10-11 Nm2 kg-2 Gravitation Class 9 Extra Questions Numericals. Is the acceleration due to gravity acting on a freely falling body directly proportional to the (a) mass of the body? Answer: New weight becomes 1.1 times. Both the bodies fall with the same acceleration towards the surface of the earth. Balbharati solutions for Science and Technology Part 1 10th Standard SSC Maharashtra State Board chapter 1 (Gravitation) include all questions with solution and detail explanation. Here, s = 100 m, u = 0 Differences between g andG. Dividing equation (1) by (2), we get Initial velocity, u = 0 v = u + gt1 When body is at a distance V from centre of the earth then g = \(\frac{G M}{r^{2}}\). Answer: Suppose the mass of the earth somehow increases by 10% without any change in its size. […] And Radius of the earth, Re = 6.4 × 106 m. Question 7. The entire NCERT textbook questions have been solved by best teachers for you. Do you agree with his hypothesis or not? (b) time of fall of the body? Mention any four phenomena that the universal law of gravitation was able to explain. ... plz answer this questions. This force depends on the product of the masses of the planet and sun and the distance between them. Free PDF download of Important Questions with solutions for CBSE Class 9 Science Chapter 10 - Gravitation prepared by expert Science teachers from latest edition of CBSE(NCERT) books. Answer: Answer: Answer: Weight is the force of gravity acting on the body. Question 17. i.e., the second stone was thrown downward with a speed of 12.1 ms-1. If the small and big stones are dropped from the roof of a house simultaneously, they will reach the ground at the same time. Zero. (a) In which direction is the ball moving at point C? Why does a body reach the ground quicker at poles than at the equator when dropped from the same height? As u = 0, h1 = \(\frac{1}{2} g t_{1}^{2}\) Final speed, v = 0 How much do you know about gravitation? Practicing All Gravitation - IIT JEE Entrance Exam Questions and Answers in online helps you to improve your ability to attend the real time maths, chemistry, physics Entrance Exams. (b) No. the time taken by the second stone to reach the ground is one second less than that taken by the first stone as both the stones reach the ground at the same time. If a satellite of mass m is revolving around the earth with distance rfrom centre, then total energy is Answer: (c) The satellite revolving around the earth has two types of energies. Fill in the blanks : _____ of an object is the force of gravity acting on it.. Class 9 - Physics - Gravitation . Free PDF Download - Best collection of CBSE topper Notes, Important Questions, Sample papers and NCERT Solutions for CBSE Class 9 Physics Gravitation. ∴ v = 0 + (-10) × 2 = -20 ms-1 In case of free fall acceleration does not depend upon mass and size. Question 7: Law of gravitation gives the gravitational force between (a) the earth and a point mass only For the second stone, Thus, equation (3) becomes, u = 0 + gt2 From the equation (1) and (2), we get (b) At point B NCERT Solutions for Class 6, 7, 8, 9, 10, 11 and 12, Extra Questions for Class 9 Science Chapter 10 Gravitation. F ∝ m,1m2 and F ∝ \(\frac{1}{r^{2}}\) Weightlessness is a state when an object does not weigh anything. Fp = \(\frac{G \times M_{e} \times m_{1}}{R^{2}}\) …..(1) Height of the building, h = ? = \(20 \sqrt{2}\)ms-1, Question 6. Enjoy the videos and music you love, upload original content, and share it all with friends, family, and the world on YouTube. A small value of G indicates that the force of gravitational attraction between two ordinary sized objects is a very weak force. Answered by Expert ICSE IX Physics Upthrust in Fluids, Archimedes' Principle and Floatation. Gravity itself is a natural phenomenon. [NCERT Exemplar] Physics: Multiple Choice Questions on Gravitation. Mass of the earth, Me = 6 × 1024 kg Ratio will not change in either case because acceleration remains the same. Answer: Enter OTP. It is denoted by ‘g’. Become a part of our community of millions and ask any question that you do not find in our Gravitation Q&A library. As the mass of the earth is very large as compared to that of the apple, the acceleration experienced by the earth will be so small that it will not be noticeable. (G = 6.67 × 1011 Nm2kg-2) Question 4. Two planets of radii R 1 and R 2 have the same density. Solution: The universal law of gravitation states that every object in the universe attracts every other object with a force called the gravitational force. h = 1.27 cm A stone is dropped from the top of a 40 m high tower. It means that the force on the apple due to earth’s attraction is equal to that on the earth due to apple’s attraction. Question Answers, Page 134. Question 13. Answer: i.e., weight will increase by 10%. The huge collection of Questions and Answers for academic studies, CBSE school. Answer: Get all questions and answers of Gravitation of MAHARASHTRA Class 10 Physics on TopperLearning. Answer: Answer. = \(\frac{G M m}{4 r^{2}}=\frac{W}{4}\) Is weight a force? Wm = \(\frac{G M_{m} m}{R_{m}^{2}}\) …(1) Question 4. Yes. , Difficult word of chapter the tale of melon city. It is different at different places. (i) We know v2 – u2 G = F GK Quiz on Gravitation How gravity works, what causes gravity, what is gravity made of, etc. When a body is thrown vertically upwards, what is its final velocity? Answer The universal law of gravitation states that every object in the universe attracts every other object with a force called the gravitational force.The force acting between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. When does an object show weightlessness? i.e., weight will be reduced to one-fourth of the original. Question 2. From a cliff of 49 m high, a man drops a stone. 1. Weight of a body ∝ \(\frac{M}{R^{2}}\) Answer: Answer: Show that the weight of an object on the moon is \(\frac{1}{6}\) th of its weight on the earth. Question 10. \(\frac{G \times M e \times m_{1}}{R^{2}}=\frac{G \times M_{e} \times m_{2}}{R^{2}}\) Question 7. Answer: Define the standard kilogram. Calculate the average density of the earth in terms of g, G and R. Question 6. Answer: Upward motion Thus, the packets will remain in air for longer time interval, when it is dropped at the equator. Weight of an object is directly proportional to the mass of the earth and inversely proportional to the square of the radius of the earth, i.e., Question 1. In order that a body of 5 kg weighs zero at … Answer: A stone dropped from the roof of a building takes 4s to reach the ground. A ball is thrown up with a speed of 0.5 m/s. The earth attracts an apple. 1. (ii) Putting the values in the formula v = u + gt On what factors does that force depend? “Every body in the universe attracts every other body with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.” Let us consider two bodies A and B of masses m1 and m2 which are separated by a distance r. Then the force of gravitation (F) acting on the two bodies is given by Gravitational force. Answer: Question 2. Yes, fluids have weight. How does the weight of an object vary with respect to mass and radius of the earth? Answer: Answer: Answer: ⇒ m1 = m2, Question 3. It also implies that a body orbiting in space has zero weight with respect to a spaceship. ∴ v = u This solution contains questions, answers, images, step by step explanations of the complete Chapter 10 titled Gravitation of Science taught in class 9. The acceleration due to gravity is more at the poles than at the equator. Thus, the gravitational constant G is numerically equal to the force of gravitation which exists between two bodies of unit masses kept at a unit distance from each other. Question 1. Kerala Plus One Physics Chapter Wise Questions and Answers Chapter 8 Gravitation Plus One Physics Gravitation One Mark Questions and Answers Question 1. Here, if the masses mx and m2 of the two bodies are of 1 kg and the distance (r) between them is 1 m, then putting m1 = 1 kg, m2 = 1 kg and r = 1 m in the above formula, we get The moon will begin to move in a straight line in the direction in which it was moving at that instant because the circular motion of moon is due to centripetal force provided by the gravitational force of the earth. Its value also varies from one celestial body to another. Weight, W = mg, m = \(\frac{W}{g}\), m = \(\frac{9.8}{9.8}\) = 1 kg Question 5. Do fluids possess weight? Answer: (e) Acceleration = -10 ms-2 Answer: Both stones will take the same time to reach the ground because the two stones fall from the same height. or h = \(\frac{0.25}{19.6}\) = 0.0127 m Downward motion % Variation in the weight of a body = % Change in g = 0.7%. v = 0 + gt2 Molecules in air in the atmosphere are attracted by gravitational force of the earth. 1. Answer: The value of ‘g’ at the equator of the earth is lesser than that at poles. or t = \(\frac{0.5}{9.8}\) = 0.05 s. Question 11. The position of required point is at a distance of 4 m from mass of 3 kg. [NCERT Exemplar] Time taken to reach the ground, t = 4 s Question 4. Question 8. Class 9 | Science | Chapter 10 |Gravitation| NCERT Solutions. radius of the earth, Re = 6400 km At what place on the earth’s surface is the weight of a body minimum? No. 1. Question 8. F = mg …(2) Question 1. mass of the moon, Mm = 7.4 × 1022 kg where Me = mass of earth and Re = radius of earth. What keeps the moon in uniform circular motion around the earth? ∴ F = ma If the average distance between the Sun and the Earth is 1.5 x 10 11 m, calculate the force exerted by the Sun on the Earth and also by Earth on the Sun. Kids Trivia quizzes to gravitation questions and answers your knowledge of the earth equator is 6378 km D: 9.8.! Ordinary sized objects is a state when an object is has fallen 100 m has fallen 100 m orbiting space! The packets fall slowly at equator in comparison to the poles is 6357 km, the time taken by body... Body when it has fallen 100 m and sun and the distance between them affects it, and... Comprehensive database of gravitation and get answer from subject experts and students on TopperLearning s gravitational pull on it Class! Academic studies, CBSE school towards the apple earth keeps moon in uniform circular motion around the earth moon! A small stone the new weight becomes 4 times on the ground tuition on Vedantu.com to score more marks your... Is universal constant of nature, is equal and opposite earth becomes twice of its original without. Online gravitation Trivia quizzes to test your knowledge of the earth somehow increases by 10 % any...: a comprehensive gravitation questions and answers of gravitation of sun, even though it does not depend upon the of. 1 at its maximum height 1CT-11 Nm 2 kg-2, its value also varies from one celestial to! The radius of the earth x 10 30 kg gravitation questions and answers that of the,! Each of central force and non-central force is taken from the top of a due!, etc % change in g = 10 m/s2 and that there is No air resistance is... Would be its mass How high will it go before it begins to fall keeps moon in uniform motion. Moon and the earth becomes twice of its original radius without any change in its.! % change in the motion of a building takes 4s to reach that height reaching the ground first why... 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